5x^2/4=20/1

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Solution for 5x^2/4=20/1 equation: 



5x^2/4=20/1

We move all terms to the left:

5x^2/4-(20/1)=0

We add all the numbers together, and all the variables

5x^2/4-0=0

We add all the numbers together, and all the variables

5x^2/4=0

We multiply all the terms by the denominator


5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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